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CGP EDU Academic Team
Published on: August 21, 2026
Find out the solubility of Ni(OH) 2 in 0.1 M NaOH. Given that the ionic product of Ni(OH) 2 is 2 x 10 -15
Text Solution
Verified by ExpertsThe correct answer is:
Product of concentrations of ions in product is known as Ionic product.



Ionic product 
2 x 10 -15 = s(0,1) 2
s = 2 x 10 -13
Solubility of Ni(OH) 2 = 2 x 10 -13 M
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